A recurrence and its general solution
Choose your method, connect the parts and explain your conclusions. These original questions include written reasoning and sketches as well as exact answer checks.
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Before you start
Linear recurrence calculation. Read the relevant method, then decide which parts you can solve without hints.
Check a misconception first · Try a connected problem
Read an original example question
, with .
Part a
Find a closed form for .
Part b
Hence find .
Part c
Verify the closed form in the original recurrence.
Model solution and review criteria
Part a
The characteristic equation λ²−5λ+6=0 has distinct roots 2,3. Thus =A2ⁿ+B3ⁿ. A+B=2 and 2A+3B=5 give A=B=1.
- Obtain the characteristic equation and both roots.
- Use two constants for a second-order recurrence.
- Apply both initial values.
Part b
The closed form gives +=35.
- Use the closed form rather than assuming a geometric sequence.
Part c
Each root t satisfies =5t−6. Multiplying by shows obeys the recurrence. Their sum obeys it too, and the initial values agree.
- Substitute or use the root identity.
- Check both initial conditions.
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