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Exact distances between coordinates

Use the horizontal and vertical displacements as the perpendicular sides of a right triangle.

For points A = (x₁,y₁) and B = (x₂,y₂), the displacement is (x₂ − x₁,y₂ − y₁). Pythagoras gives AB² = (x₂ − x₁)² + (y₂ − y₁)². The order of subtraction does not change the distance because the displacements are squared. Keep negative coordinate values inside brackets when subtracting.

Distance is nonnegative and is zero exactly when the points coincide. Simplify a square root by extracting square factors, and retain the exact answer unless a decimal is requested. To compare two lengths, compare their squares when both are nonnegative. This lets you check for equal sides while keeping the square roots exact.

Worked example

Find the exact distance from A = (−1,2) to B = (5,5).

  1. The horizontal displacement is 5 − (−1) = 6; the vertical displacement is 5 − 2 = 3.
  2. The distance squared is 6² + 3² = 45.
  3. Take the nonnegative root and extract the square factor 9.

Answer: AB = √45 = 3√5.

Practise exact distances between coordinates

Course mapping

These specification references show where the topic occurs. The questions cover only some parts of each topic.

Next practice: Pythagoras in three dimensions, Midpoints and section ratios.