Linear sequence nth terms
Use the constant difference to find the coefficient of n.
Read the lesson: Arithmetic sequences and sums
For a sequence with first term a and constant difference d, the nth term is a + (n − 1)d. The index of the first listed term is 1. Expanding gives dn + (a − d), which makes it easy to check the first term. Negative differences give decreasing sequences.
To decide whether a value occurs, equate the nth-term expression to that value and solve for n. The answer must be a positive integer. Symbolic first terms work in the same way: subtract consecutive terms to find their common difference, then retain the symbols during simplification. A constant second difference describes a quadratic sequence and needs a different nth-term model.
Worked example
The sequence starts 17, 12, 7, 2, … . Find its nth term and decide whether −98 occurs.
- The difference is −5, so uₙ = 17 − 5(n − 1) = 22 − 5n.
- Solve 22 − 5n = −98 to obtain n = 24.
- The index 24 is a positive integer.
Answer: uₙ = 22 − 5n; −98 is the 24th term
Practise linear sequence nth terms
Course mapping
These specification references show where the topic occurs. The questions cover only some parts of each topic.
- 8365 · core · 2.21: Linear sequence nth terms
- 9FM0 · core · Assumed A-level Mathematics knowledge: Linear sequence nth terms
- 7367 · core · Assumed A-level Mathematics knowledge: Linear sequence nth terms
- H245 · core · Assumed A-level Mathematics knowledge: Linear sequence nth terms
- H645 · core · Assumed A-level Mathematics knowledge: Linear sequence nth terms
- 4PM1 · core · 5B: Linear sequence nth terms
Next practice: Quadratic sequences, Sequence terms and limiting values.